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Oracle Introduction to Oracle9i: SQL Sample Questions:

1. What is true about sequences?

A) Once created, a sequence is automatically available to all users.
B) Only the DBA can control which sequence is used by a certain table.
C) Once created, a sequence belongs to a specific schema.
D) Once created, a sequence is automatically used in all INSERT and UPDATE statements.
E) Once created, a sequence is linked to a specific table.

2. Which two statements about subqueries are true? (Choose two.)

A) A single row subquery can retrieve data from only one table.
B) A SQL query statement cannot display data from table B that is referred to in its subquery, unless table B is included in the main query's FROM clause.
C) A single row subquery can retrieve data from more than one table.
D) A SQL query statement can display data from table B that is referred to in its subquery, without including table B in its own FROM clause.
E) A single row subquery cannot be used in a condition where the LIKE operator is used for comparison.
F) A multiple-row subquery cannot be used in a condition where the LIKE operator is used for comparison.

3. Examine the data from the ORDERS and CUSTOMERS table.

Which SQL statement retrieves the order ID, customer ID, and order total for the orders that are placed on the same day that Martin places his orders?

A) SELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders, customers Where cust_name = 'Martin');
B) SELECT ord_id, cust_id, ord_total FROM orders WHERE cust_id IN (SELECT cust_id FROM customers WHERE cust name = 'Martin');
C) SELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders WHERE cust_id = (SELECT cust_id FROM customers WHERE cust_name = 'Martin'));
D) SELECT ord_id, cust_id, ord_total
FROM orders, customers
WHERE cust_name='Mating'
AND ord_date IN ('18-JUL-2000','21-JUL-2000');

4. Examine the data in the EMPLOYEES and DEPARTMENTS tables.

You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?

A) SELECT last_name, department_name FROM employees , departments(+);
B) SELECT last_name, department_name FROM employees(+) , departments ON (e.department_id = d.department_id);
C) SELECT last_name, department_name FROM employees(+) e JOIN departments d ON (e.department_id = d.department_id);
D) SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
E) SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);
F) SELECT last_name, department_name FROM employees JOIN departments (+);

5. Examine the data of the EMPLOYEES table.
EMPLOYEES (EMPLOYEE_ID is the primary key. MGR_ID is the ID of managers and refers to the EMPLOYEE_ID)

Which statement lists the ID, name, and salary of the employee, and the ID and name of the employee's manager, for all the employees who have a manager and earn more than 4000?

A) SELECT employee_id "Emp_id", emp_name "Employee",
salary,
employee_id "Mgr_id", emp_name "Manager"
FROM employees
WHERE salary > 4000;
B) mgr_id "Mgr_id", m.emp_name "manager"
FROM employees e, employees m
WHERE e.mgr_id = m.employee_id
AND e.salary > 4000;
C) SELECT e.employee_id "Emp_id", e.emp_name "Employee",
D) SELECT e.employee_id "Emp_id", e.emp_name "Employee",
E) salary,
F) employee_id "Mgr_id", m.emp_name "Manager"
FROM employees e, employees m
WHERE e.mgr_id = m.employee_id
AND e.salary > 4000;
G) salary,
H) employee_id "Mgr_id", m.emp_name "Manager"
FROM employees e, employees m
WHERE e.mgr_id = m.mgr_id
AND e.salary > 4000;
I) SELECT e.employee_id "Emp_id", e.emp_name "Employee",
J) SELECT e.employee_id "Emp_id", e.emp_name "Employee",
K) salary,
L) salary,
M) mgr_id "Mgr_id", m.emp_name "Manager"
FROM employees e, employees m
WHERE e.employee_id = m.employee_id
AND e.salary > 4000;

Solutions: