Microsoft 070-457 - PDF電子當

070-457 pdf
  • 考試編碼:070-457
  • 考試名稱:Transition Your MCTS on SQL Server 2008 to MCSA: SQL Server 2012, Part 1
  • 更新時間:2025-06-25
  • 問題數量:172 題
  • PDF價格: $59.98
  • 電子當(PDF)試用

Microsoft 070-457 超值套裝
(通常一起購買,贈送線上版本)

070-457 Online Test Engine

在線測試引擎支持 Windows / Mac / Android / iOS 等, 因爲它是基於Web瀏覽器的軟件。

  • 考試編碼:070-457
  • 考試名稱:Transition Your MCTS on SQL Server 2008 to MCSA: SQL Server 2012, Part 1
  • 更新時間:2025-06-25
  • 問題數量:172 題
  • PDF電子當 + 軟件版 + 在線測試引擎(免費送)
  • 套餐價格: $119.96  $79.98
  • 節省 50%

Microsoft 070-457 - 軟件版

070-457 Testing Engine
  • 考試編碼:070-457
  • 考試名稱:Transition Your MCTS on SQL Server 2008 to MCSA: SQL Server 2012, Part 1
  • 更新時間:2025-06-25
  • 問題數量:172 題
  • 軟件版價格: $59.98
  • 軟件版

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Free Download 070-457 pdf braindumps

最新的 MCSA 070-457 免費考試真題:

1. You administer a Microsoft SQL Server 2012 database that includes a table named Products. The Products table has columns named Productld, ProductName, and CreatedDateTime. The table contains a unique constraint on the combination of ProductName and CreatedDateTime. You need to modify the Products table to meet the following requirements:
Remove all duplicates of the Products table based on the ProductName column.
Retain only the newest Products row. Which Transact-SQL query should you use?

A) WITH CTEDupRecords AS (
SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
HAVING COUNT(*) > 1
)
DELETE p
FROM Products p
JOIN CTEDupRecords cte ON
cte.ProductName = p.ProductName
AND cte.CreatedDateTime > p.CreatedDateTime
B) WITH CTEDupRecords AS (
SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
HAVING COUNT(*) > 1
)
DELETE p
FROM Products p
JOIN CTEDupRecords cte ON
p.ProductName = cte.ProductName
C) WITH CTEDupRecords AS (
SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
HAVING COUNT(*) > 1
)
DELETE p
FROM Products p
JOIN CTEDupRecords cte ON
p.ProductName = cte.ProductName
AND p.CreatedDateTime > cte.CreatedDateTime
D) WITH CTEDupRecords AS (
SELECT MIN(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
)
DELETE p
FROM Products p
JOIN CTEDupRecords cte ON
p.ProductName = cte.ProductName


2. You use Microsoft SQL Server 2012 to develop a database application. You create a table by using the following definition:
CREATE TABLE Prices (
PriceId int IDENTITY(1,1) PRIMARY KEY,
ActualPrice NUMERIC(16,9),
PredictedPrice NUMERIC(16,9) )
You need to create a computed column based on a user-defined function named udf_price_index. You also need to ensure that the column supports an index. Which three Transact-SQL statements should you use? (To answer, move the appropriate SQL statements from the list of statements to the answer area and arrange them in the correct order.)
Build List and Reorder:


3. You administer a Microsoft SQL Server 2012 instance that contains a financial database hosted on a storage area network (SAN). The financial database has the following characteristics:
A data file of 2 terabytes is located on a dedicated LUN (drive D).
A transaction log of 10 GB is located on a dedicated LUN (drive E).
Drive D has 1 terabyte of free disk space.
Drive E has 5 GB of free disk space.
The database is continually modified by users during business hours from Monday through Friday between
09:00
hours and 17:00 hours. Five percent of the existing data is modified each day. The Finance department loads large CSV files into a number of tables each business day at 11:15 hours and 15:15 hours by using the BCP or BULK INSERT commands. Each data load adds 3 GB of data to the database. These data load operations must occur in the minimum amount of time. A full database backup is performed every Sunday at 10:00 hours. Backup operations will be performed every two hours (11:00, 13:00, 15:00, and 17:00) during business hours. You need to ensure that the minimum amount of data is lost. Which recovery model should the database use?

A) CONTINUE_AFTER_ERROR
B) SIMPLE
C) FULL
D) COPY_ONLY
E) NORECOVERY
F) CHECKSUM
G) Differential
H) SKIP
I) DBO_ONLY
J) Transaction log
K) NO_CHECKSUM
L) RESTART
M) STANDBY
N) BULK_LOGGED


4. You use Microsoft SQL Server 2012 to create a stored procedure as shown in the following code segment. (Line numbers are included for reference only.)

The procedure can be called within other transactions. You need to ensure that when the DELETE statement from the HumanResourcesJobCandidate table succeeds, the modification is retained even if the insert into the Audit.Log table fails. Which code segment should you add to line 14?

A) IF @@TRANCOUNT = 1
B) IF (XACT_STATE ( ) ) = 0
C) IF @@TRANCOUNT = 0
D) IF (XACT_STATE ( ) ) = 1


5. You are a database developer for an application hosted on a Microsoft SQL Server 2012 server. The database contains two tables that have the following definitions:

Global customers place orders from several countries. You need to view the country from which each customer has placed the most orders. Which Transact-SQL query do you use?

A) SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs
WHERE Rnk = 1
B) SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
C) SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY OrderAmount DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
D) SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) DESC) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC


問題與答案:

問題 #1
答案: A
問題 #2
答案: 僅成員可見
問題 #3
答案: N
問題 #4
答案: D
問題 #5
答案: B

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