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ASCP MEDICAL LABORATORY TECHNICIAN - MLT(ASCP) Sample Questions:
1. A patient with tuberculosis would be placed in:
A) protective isolation.
B) body fluid isolation.
C) droplet isolation.
D) airborne isolation.
2. Deviations from Beer's Law are caused by:
A) very low concentration of absorbing material
B) polychromatic light
C) stray light
D) very high concentrations of substance being measured in a colorimetric reaction
3. The Clinical Laboratory and Standards Institure (CLSI) recommends that all patient specimens are delivered to the laboratory no more than 2 hours after collection to reduce pre-examination variables caused by cellular action and the effects of prolonged exposure of specimens to room temperatures, such as:
Question options:
A) glycolysis caused by exposure to room temperatures; hemolysis and leakage of coagulation factors from the cells; decreased potassium levels in the serum and plasma by cellular utilization
B) glycolysis caused by cells' use of glucose; hemolysis and leakage of potassium from the cells into the plasma or serum; the destruction of coagulation factors from exposure to room temperatures
C) glycolysis caused by leakage from cells; increased levels of coagulation factors caused by prolonged exposure to room temperatures; decreased potassium levels caused by cellular metabolism
D) leakage of coagulation factors into the serum or plasma by cellular metabolism; increased potassium values caused by exposure to room temperature; increased glucose values caused by cellular metabolism
4. Measuring the turnaround times of troponin tests from the emergency department would provide valuable information. This data represents circumstances in which patient safety may be compromised if results are delayed and treatment is not started as soon as possible.
A laboratory manager wants to evaluate the timeliness of patient services in order to prevent medical errors caused by delay in treatment. Measuring the turnaround time for which of these analytes would provide the most valuable information?
A) Routine glucose tests from patients on medical floors
B) Troponin tests from the emergency department
C) Lipid panels from the outpatient clinic
5. The colonies seen growing on the bird seed agar appear smooth and have a distinct reddish-brown pigmentation. The active ingredient in bird seed (Guizotia abyssinica) agar is caffeic acid, which is extracted and placed in an agar containing 1% glucose. Of the cryptococci, and other species of yeasts, Cryptococcus neoformans selectively produces the enzyme phenoloxidase, which oxidizes the caffeic acid in the medium to melanin, producing the red-brown pigmentation.
The other yeast species included in this exercise do not possess phenoloxidase activity and therefore remain non-pigmented when grown on bird seed agar.
The colonies shown in this photograph were grown on Guizotia abyssinica (bird seed) agar at 30°C for 72 hours. The most likely identification is:
A) Saccharomyces cerevisiae
B) Candida parapsilosis
C) Cryptococcus neoformans
D) Cryptococcus laurentii
Solutions:
Question # 1 Answer: D | Question # 2 Answer: C | Question # 3 Answer: B | Question # 4 Answer: B | Question # 5 Answer: C |