安全具有保證的 1Z0-007 題庫資料

在談到 1Z0-007 最新考古題，很難忽視的是可靠性。我們是一個為考生提供準確的考試材料的專業網站，擁有多年的培訓經驗，Oracle 1Z0-007 題庫資料是個值得信賴的產品，我們的IT精英團隊不斷為廣大考生提供最新版的 Oracle 1Z0-007 認證考試培訓資料，我們的工作人員作出了巨大努力，以確保考生在 1Z0-007 考試中總是取得好成績，可以肯定的是，Oracle 1Z0-007 學習指南是為你提供最實際的認證考試資料，值得信賴。

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我們為你提供通过 Oracle 1Z0-007 認證的有效題庫，來贏得你的信任。實際操作勝于言論，所以我們不只是說，還要做，為考生提供 Oracle 1Z0-007 試題免費試用版。你將可以得到免費的 1Z0-007 題庫DEMO，只需要點擊一下，而不用花一分錢。完整的 Oracle 1Z0-007 題庫產品比試用DEMO擁有更多的功能，如果你對我們的試用版感到滿意，那么快去下載完整的 Oracle 1Z0-007 題庫產品，它不會讓你失望。

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通過 Oracle 1Z0-007 認證考試是不簡單的，選擇合適的考古題資料是你成功的第一步。因為好的題庫產品是你成功的保障，所以 Oracle 1Z0-007 考古題就是好的保障。Oracle 1Z0-007 考古題覆蓋了最新的考試指南，根據真實的 1Z0-007 考試真題編訂，確保每位考生順利通過 Oracle 1Z0-007 考試。

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最新的 9i DBA 1Z0-007 免費考試真題:

1. Which SQL statement returns a numeric value?

A) SELECT TO_NUMBER(hire_date + 7) FROM EMP;
B) SELECT sysdate-hire_date FROM EMP;
C) SELECT ADD_MONTHS(MAX(hire_Date), 6) FROM EMP;
D) SELECT ROUND(hire_date) FROM EMP;

2. You need to modify the STUDENTS table to add a primary key on the STUDENT_ID column. The table is currently empty.
Which statement accomplishes this task?

A) ALTER TABLE students ADD PRIMARY KEY student_id;
B) ALTER TABLE students ADD CONSTRAINT PRIMARY KEY (student_id);
C) ALTER TABLE students ADD CONSTRAINT stud_id_pk PRIMARY KEY student_id;
D) ALTER TABLE studentsMODIFY CONSTRAINT stud_id_pk PRIMARY KEY (student_id);
E) ALTER TABLE students ADD CONSTRAINT stud_id_pk PRIMARY KEY (student_id);

3. Examine the structure of the STUDENTS table:

You need to create a report of the 10 students who achieved the highest ranking in the course INT SQL and who completed the course in the year 1999.
Which SQL statement accomplishes this task?

A) SELECT student_id, marks, ROWNUM "Rank"
FROM (SELECT student_id, marks
FROM students
WHERE ROWNUM <= 10
AND finish_date BETWEEN '01-JAN-99' AND
'31-DEC-99'
AND course_id = 'INT_SQL'
ORDER BY marks DESC);
B) SELECT student_ id, marks, ROWNUM "Rank"
FROM students
WHERE ROWNUM <= 10
AND finish_date BETWEEN '01-JAN-99' AND '31-DEC-99'
AND course_id = 'INT_SQL'
ORDER BY marks DESC;
C) SELECT student_id, marks, ROWID "Rank"
FROM students
WHERE ROWID <= 10
AND finish_date BETWEEN '01-JAN-99' AND '31-DEC-99'
AND course_id = 'INT_SQL'
ORDER BY marks;
D) SELECT student_id, marks, ROWNUM "Rank"
FROM (SELECT student_id, marks
FROM students
ORDER BY marks DESC)
WHERE ROWNUM <= 10
AND finish_date BETWEEN '01-JAN-99' AND '31-DEC-99'
AND course_id = 'INT_SQL';

4. Examine the structure of the EMPLOYEES and NEW_EMPLOYEES tables:

Which DELETE statement is valid?

A) DELETE FROM employees
WHERE employee_id IN (SELECT employee_id
FROM new_employees
WHERE name = 'Carrey');
B) DELETE FROM employees
WHERE employee_id = (SELECT employee_id FROM employees);
C) DELETE * FROM employees
WHERE employee_id IN (SELECT employee_id
FROM new_employees
WHERE name = 'Carrey');
D) DELETE * FROM employees
WHERE employee_id=(SELECT employee_id FROM new_employees);

5. Exhibit

Examine the data in the EMPLOYEES and DEPARTMENTS tables.
You want to retrieve all employees' last names, along with their manager's last names and their department names. Which query would you use?

A) SELECT e.last_name, m.last_name, department_name
FROM employees e
RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id)
RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id)
B) SELECT last_name, manager_id, department_name
FROM employees e
JOIN departments d ON (e.department_id = d.department_id) ;
C) SELECT e.last_name, m.last_name, department_name
FROM employees e
RIGT OUTER JOIN employees m on ( e.manager_id = m.employee_id)
LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
D) SELECT e.last_name, m.last_name, department_name
FROM employees e
LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id)
RIGT OUTER JOIN departments d ON (e.department_id = d.department_id);
E) SELECT last_name, manager_id, department_name
FROM employees e
FULL OUTER JOIN departments d ON (e.department_id = d.department_id);
F) SELECT e.last_name, m.last_name, department_name
FROM employees e
LEFT OUTER JOIN employees m on ( e.managaer_id = m.employee_id)
LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);

問題與答案：