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最新的 Certified Solution Designer C2070-987 免費考試真題:

1. IBM Content Manager Java components (for example, Content Manager API, Content Manager resource manager application server and DB2 Text Search document constructor) support a set of security levels based on federal standards From lowest to highest security, these levels are:
None
FIPS (Federal Information Processing Standard), defined as FIPS 140-2 - Transitional, defined as SP 000-131 Transitional
Strict, defined as SP 80O-131 Strict
Suite-B-128. defined as CNSSP-1G (Committee on Matronal Security Systems Policy Number 15)
Suite B-192. defined as CNSSP-15
If a system administrator uses an Oracle database and configures all connections for TLS, which is the highest overall security setting that can be applied?

A) Strict
B) None
C) Transitional
D) FIPS

2. An IBM Content Manager solution designer is designing a system which requires a certain level of Transport Layer Security (TLS).
Which of the following components need to be configured to use Net Search Extender with TLS?

A) Library server only
B) Both library server and resource manager,
C) The database connections to library server and resource manager.
D) Resource manager only.

3. Which of the allowing concepts is NOT related to remote configuration?

A) Source machine
B) Target machine
C) Configuration profile
D) Reference machine

4. A training company manages all training material using IBM Content Manager. The data model is designed as follows:
1.An item type COURSE is created to hold the course information. Each item in this item type is afolder representing a course. The content of these folders, are documents that constitutes thematerial of the course.
2.A resource item type MATERIAL is used to store all the course material. Each item in this item type is a document such as assignments, class presentations, videos.
3.Items in item type COURSE are linked to Material items to indicate which material belongs to which course.
All students and instructors use the same application to search for and retrieve the course, the course Information and materials from the COURSE and MATERIAL item types. The solution designer needs to design the authorization method to allow the student to retrieve only the course information for which they registered.
Assume the solution designer has sat the ACL binding level to item binding for both of the item types.
There are N courses: course 1 to courseN,
STUDENTn= the user group includes students registered in courseN
ALL STUDENT = the user group includes all students
Read PriveSet = privilege set containing privileges allowing read access to items. This privilege set is assigned to all instructors
How should the solution designer create the ACL(S) items in COURSE to satisfy student access requirements?

A) Turn on Public enable access, then create N number of ACLs. ACL 1, AGL2, ,,,,,ACLn for each courseN. Each ACLn has 1 rule (ICMPUBLC. readPrivSet).
B) Create 1 ACL with rule (ALLSTUDENTS, readPrivSet)
C) Create 1 ACL containing N rules: (STUDENT1. readPrivSet), (STUDENT2. readPrivSet),.... (STUDENTn. readPrivSet).
D) Create n ACLs: ACL1. ACL2. ....ACLn for each courseN- Each ACLn has 1 rule (STUDENTn,readPrivSel).

5. To avoid impacting the business operating during day time, the company decides to run the replication service every night from 11PM to 5AM. The customer is in a time zone of GMT+8.
Which of the Following is the correct way to manage the replicator service?

A) Keep the replicator started. Set the replicator schedule as: Every day; Start at=15 OO; Duration Hours=6
B) Keep the replicator started Set the replicator schedule as: Every day; Start at=23 GO: Duration Hours=6
C) By calling utility IBMCMROOT/bin ManageService (sh/bat). start the replicator service at 23:00and stop the replicator service at 5:00- Sat the replicator schedule as: Every day Start at=00.00. Duration Hours= 24
D) By calling utility I EMCMROOT/bin/manageService.(sh/bat). start the replicator service at 15:00and stop the replicator service at 21:00. Set the replicator schedule as: Everyday; Start at=00 00; Duration Hours= 24

問題與答案：