Databricks Associate-Developer-Apache-Spark - PDF電子當

Associate-Developer-Apache-Spark pdf
  • 考試編碼:Associate-Developer-Apache-Spark
  • 考試名稱:Databricks Certified Associate Developer for Apache Spark 3.0 Exam
  • 更新時間:2025-10-29
  • 問題數量:179 題
  • PDF價格: $59.98
  • 電子當(PDF)試用

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  • 考試編碼:Associate-Developer-Apache-Spark
  • 考試名稱:Databricks Certified Associate Developer for Apache Spark 3.0 Exam
  • 更新時間:2025-10-29
  • 問題數量:179 題
  • PDF電子當 + 軟件版 + 在線測試引擎(免費送)
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Associate-Developer-Apache-Spark Testing Engine
  • 考試編碼:Associate-Developer-Apache-Spark
  • 考試名稱:Databricks Certified Associate Developer for Apache Spark 3.0 Exam
  • 更新時間:2025-10-29
  • 問題數量:179 題
  • 軟件版價格: $59.98
  • 軟件版

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最新的 Databricks Certification Associate-Developer-Apache-Spark 免費考試真題:

1. The code block shown below should write DataFrame transactionsDf to disk at path csvPath as a single CSV file, using tabs (\t characters) as separators between columns, expressing missing values as string n/a, and omitting a header row with column names. Choose the answer that correctly fills the blanks in the code block to accomplish this.
transactionsDf.__1__.write.__2__(__3__, " ").__4__.__5__(csvPath)

A) 1. coalesce(1)
2. option
3. "colsep"
4. option("nullValue", "n/a")
5. path
B) 1. csv
2. option
3. "sep"
4. option("emptyValue", "n/a")
5. path
* 1. repartition(1)
2. mode
3. "sep"
4. mode("nullValue", "n/a")
5. csv
C) 1. coalesce(1)
2. option
3. "sep"
4. option("header", True)
5. path
D) 1. repartition(1)
2. option
3. "sep"
4. option("nullValue", "n/a")
5. csv
(Correct)


2. Which of the following code blocks writes DataFrame itemsDf to disk at storage location filePath, making sure to substitute any existing data at that location?

A) itemsDf.write.mode("overwrite").parquet(filePath)
B) itemsDf.write().parquet(filePath, mode="overwrite")
C) itemsDf.write(filePath, mode="overwrite")
D) itemsDf.write.mode("overwrite").path(filePath)
E) itemsDf.write.option("parquet").mode("overwrite").path(filePath)


3. The code block displayed below contains an error. The code block should return a copy of DataFrame transactionsDf where the name of column transactionId has been changed to transactionNumber. Find the error.
Code block:
transactionsDf.withColumn("transactionNumber", "transactionId")

A) Each column name needs to be wrapped in the col() method and method withColumn should be replaced by method withColumnRenamed.
B) The arguments to the withColumn method need to be reordered and the copy() operator should be appended to the code block to ensure a copy is returned.
C) The method withColumn should be replaced by method withColumnRenamed and the arguments to the method need to be reordered.
D) The copy() operator should be appended to the code block to ensure a copy is returned.
E) The arguments to the withColumn method need to be reordered.


4. The code block displayed below contains an error. The code block is intended to perform an outer join of DataFrames transactionsDf and itemsDf on columns productId and itemId, respectively.
Find the error.
Code block:
transactionsDf.join(itemsDf, [itemsDf.itemId, transactionsDf.productId], "outer")

A) The "outer" argument should be eliminated from the call and join should be replaced by joinOuter.
B) The "outer" argument should be eliminated, since "outer" is the default join type.
C) The term [itemsDf.itemId, transactionsDf.productId] should be replaced by itemsDf.itemId == transactionsDf.productId.
D) The term [itemsDf.itemId, transactionsDf.productId] should be replaced by itemsDf.col("itemId") == transactionsDf.col("productId").
E) The join type needs to be appended to the join() operator, like join().outer() instead of listing it as the last argument inside the join() call.


5. Which of the following code blocks returns a single row from DataFrame transactionsDf?
Full DataFrame transactionsDf:
1.+-------------+---------+-----+-------+---------+----+
2.|transactionId|predError|value|storeId|productId| f|
3.+-------------+---------+-----+-------+---------+----+
4.| 1| 3| 4| 25| 1|null|
5.| 2| 6| 7| 2| 2|null|
6.| 3| 3| null| 25| 3|null|
7.| 4| null| null| 3| 2|null|
8.| 5| null| null| null| 2|null|
9.| 6| 3| 2| 25| 2|null|
10.+-------------+---------+-----+-------+---------+----+

A) transactionsDf.select("productId", "storeId").where("storeId == 2 OR storeId != 25")
B) transactionsDf.where(col("value").isNull()).select("productId", "storeId").distinct()
C) transactionsDf.filter((col("storeId")!=25) | (col("productId")==2))
D) transactionsDf.filter(col("storeId")==25).select("predError","storeId").distinct()
E) transactionsDf.where(col("storeId").between(3,25))


問題與答案:

問題 #1
答案: D
問題 #2
答案: A
問題 #3
答案: C
問題 #4
答案: C
問題 #5
答案: D

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